7x^2+4x-8=11x+6

Solution for 7x^2+4x-8=11x+6 equation:

7x^2+4x-8=11x+6

We move all terms to the left:

7x^2+4x-8-(11x+6)=0

We get rid of parentheses

7x^2+4x-11x-6-8=0

We add all the numbers together, and all the variables

7x^2-7x-14=0

a = 7; b = -7; c = -14;
Δ = b2-4ac
Δ = -72-4·7·(-14)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-21}{2*7}=\frac{-14}{14}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+21}{2*7}=\frac{28}{14}
=2
$